Kamis, 11 Mei 2017

using english to calculate



What do cookies and chemistry have in common? Many things, it turns out! A balanced chemical equation is the recipe for a reaction: it contains a list of all the reactants (the ingredients) and products (the cookies) as well as their relative proportions.
Using a balanced chemical equation to calculate amounts of reactants and products is called stoichiometry. It is a super technical-sounding word that simply means using ratios from the balanced equation. In this article, we will discuss how to use mole ratios to calculate the amount of reactants needed for a reaction.
Balanced reactions and mole ratios
The stoichiometric coefficients are the numbers we use to make sure our equation is balanced. We can make ratios using the stoichiometric coefficients, and the ratios will tell us about the relative proportions of the chemicals in our reaction. You might see this ratio called the mole ratio, the stoichiometric factor, or the stoichiometric ratio. The mole ratio can be used as a conversion factor between different quantities.

Problem solving tip: The first and most important step for all stoichiometry problems is the same no matter what you are solving for—make sure your equation is balanced! If the equation is not balanced, the mole ratios will be wrong, and the answers will not be correct.
For example, the stoichiometric coefficients for the following balanced equation tell us that 1 mole of Fe2O3 wiil react with 2 moles of Al to yield 2 moles of Fe and 1 moles of AL2O3.
            Fe2O3(s) + 2Al (s)               2Fe(l) + Al2O3

If we have a known mass of the reactant Fe2O3, we can calculate how many moles of Al we need to fully react with the Fe2O3 using the ratio of their coefficients:

Mole ratio between Al and Fe2O3 = 2mole Al/1mole Fe2O3
Example: Using mole ratios to calculate mass of a reactant
For the following unbalanced reaction, how many grams of NaOH will be required to fully react with 3.10 grams of H2SO4 ?

NaOH(aq)+H2SO4(aq)→H2O+Na2SO4(aq)       Not balanced!
For this reaction, we have 1 Na and 3 H on the reactant side and 2 Na and 2 H on the product side. We can balance our equation by multiplying NaOH by two—so that there are 2 Na on each side—and multiplying H2O on both sides. That gives the following balanced reaction:

2NaOH(aq)+H2SO4(aq)→2H2O+Na2SO4(aq)    Balanced!
Once we have the balanced equation, we can ask ourselves the following questions:
  • For which reactant(s) do we already know the amount of the chemical?
  • What are we trying to calculate?
In this example, we know the amount of H2SO4 is 3.10 grams, and we would like to calculate the mass of NaOH. Armed with the balanced equation and a clear sense of purpose—hopefully—we can use the following strategy to tackle this stoichiometry problem:
Step 1: Convert known reactant amount to moles.
The known quantity in this problem is the mass of H2SO4. We can convert the mass of H2SO4 to moles using the molecular weight. Given that the molecular weight of H2SO4 is 98.09 g/mol, we can find the moles of H2SO4

Step 2: Use mole ratio to find moles of other reactant.
We are interested in calculating the amount of NaOH so we can use the mole ratio between NaOH and H2SO4. Based on our balanced chemical equation, we need 2 moles of NaOH for every 1 mole of H2SO4, which gives the following ratio:

Mole ratio between NaOH and H2SO4=2mol NaOH/1mol H2SO4 or 1mol H2SO4/2mol NaOH
Each format gives a different answer! However, only one ratio will allow the units of H2SO4 to cancel out properly.
Step 3: Convert moles to mass.
We can convert the moles of NaOH from Step 2 to mass in grams using the molecular weight of NaOH:
We will need 2.53 grams of NaOH to fully react with 3.10 grams of H2SO4 in this reaction.

Shortcut: We could also combine all three steps into a single calculation, with the caveat that we should pay extra close attention to our units. In order to convert the mass of H2SO4 to mass of NaOH, we could solve the following expression:
If we look carefully at the expression, we can break it down into steps 1 to 3 above. The only difference is that instead of doing each conversion separately, we did them all at once.
Summary
The coefficients from the balanced chemical reaction tell us the proportions of the reactants and products. We can use ratios of the coefficients to convert between amounts of reactants and products in our reaction.

20 komentar:

  1. How to equalize chemical reactions ?

    BalasHapus
    Balasan
    1. you can use stoichiometry to equalize chemical reaction. and the step to equal is stoichiometric ratio

      Hapus
  2. Explain to me,If we Balanced reactions and mole ratios what use formula?

    BalasHapus
    Balasan
    1. The stoichiometric coefficients are the numbers we use to make sure our equation is balanced. We can make ratios using the stoichiometric

      Hapus
  3. Komentar ini telah dihapus oleh pengarang.

    BalasHapus
    Balasan

    1. example
      Calculate the relative formula mass of the compound with the formula: Fe2(SO4)3

      Answer

      (Fe = 56, S = 32, O = 16)

      Fe2(SO4)3
      (2 x Fe) (3 x S) (12 x O)
      (2 x 56) (3 x 32) (12 x 16)
      112 96 192
      112 + 96 + 192 = 400

      Hapus
  4. What is the difference of molarity with molality?

    BalasHapus
    Balasan
    1. Molarity, also known as molar concentration, is the number of moles of a substance per liter of solution. Solutions labeled with the molar concentration are denoted with a capital M. A 1.0 M solution contains 1 mole of solute per liter of solution.​

      Molality is the number of moles of solute per kilogram of solvent. It is important the mass of solvent is used and not the mass of the solution. Solutions labeled with molal concentration are denoted with a lower case m. A 1.0 m solution contains 1 mole of solute per kilogram of solvent.​

      The important part of remembering the difference is:

      molarity - M → moles per liter solution
      molality - m → moles per kilogram solvent

      Hapus
  5. Can you give examples of stoichiometric application in everyday life?

    BalasHapus
    Balasan
    1. In practical life, battery cells, in corrosion of House painting, amount of water pollution etc. everything is measured in terms of relative weights a.k.a Atomic mass units.

      Hapus
  6. Balasan
    1. In chemistry, molarity is a concentration unit, defined to be the number of moles of solute divided by the number of liters of solution.There are two big advantages of using molarity to express concentration. The first advantage is that it's easy and convenient to use because the solute may be measured in grams, converted
      into moles, and mixed with a volume.
      The second advantage is that the sum of the molar concentrations is thetotal molar concentration. This permits calculations of density and ionic strength.

      Hapus
  7. In the reaction between magnesium metal as much as 10 grams with 6 grams of oxygen according to the equation of the reaction:
    2Mg (s) + O2 (g) 2MgO (S)
    Apparently from the experiment generated 15 grams of magnesium as much as 1 gram. This fact is according to the law ..... (Ar Mg = 24, O = 16). Whether this is included in Dalton's law, lavoiser, Boyle, proust, or Gay lussac.

    BalasHapus
  8. In the reaction between magnesium metal as much as 10 grams with 6 grams of oxygen according to the equation of the reaction:
    2Mg (s) + O2 (g) 2MgO (S)
    Apparently from the experiment generated 15 grams of magnesium as much as 1 gram. This fact is according to the law ..... (Ar Mg = 24, O = 16). Whether this is included in Dalton's law, lavoiser, Boyle, proust, or Gay lussac.

    BalasHapus
    Balasan
    1. it's including in proust's law, proust's law Says that the mass ratio of elements in a compound is certain and fixed

      Hapus
  9. Explain to me,If we Balanced reactions and mole ratios what use formula?

    BalasHapus
  10. Please Explain the important points of the materi.?

    BalasHapus
    Balasan
    1. Using a balanced chemical equation to calculate amounts of reactants and products is called stoichiometry

      Hapus
  11. How to Balanced reactions and mole ratios in easy way?

    BalasHapus
    Balasan
    1. The first and most important step for all stoichiometry problems is the same no matter what you are solving for—make sure your equation is balanced! If the equation is not balanced, the mole ratios will be wrong, and the answers will not be correct.
      For example, the stoichiometric coefficients for the following balanced equation tell us that 1 mole of Fe2O3 wiil react with 2 moles of Al to yield 2 moles of Fe and 1 moles of AL2O3.
      Fe2O3(s) + 2Al (s) 2Fe(l) + Al2O3

      If we have a known mass of the reactant Fe2O3, we can calculate how many moles of Al we need to fully react with the Fe2O3 using the ratio of their coefficients:

      Mole ratio between Al and Fe2O3 = 2mole Al/1mole Fe2O3

      Hapus