What do cookies and chemistry have in common? Many
things, it turns out! A balanced chemical equation is the recipe for a
reaction: it contains a list of all the reactants (the ingredients) and
products (the cookies) as well as their relative proportions.
Using a balanced chemical equation to calculate
amounts of reactants and products is called stoichiometry. It is a super
technical-sounding word that simply means using ratios from the balanced
equation. In this article, we will discuss how to use mole ratios to calculate
the amount of reactants needed for a reaction.
Balanced reactions and mole ratios
The stoichiometric coefficients are the numbers we use
to make sure our equation is balanced. We can make ratios using the
stoichiometric coefficients, and the ratios will tell us about the relative
proportions of the chemicals in our reaction. You might see this ratio called
the mole ratio, the stoichiometric factor, or the stoichiometric ratio. The
mole ratio can be used as a conversion factor between different quantities.
Problem
solving tip: The first
and most important step for all stoichiometry problems is the same no matter
what you are solving for—make sure your equation is balanced! If the
equation is not balanced, the mole ratios will be wrong, and the answers will
not be correct.
For example, the stoichiometric coefficients for the
following balanced equation tell us that 1 mole of Fe2O3 wiil
react with 2 moles of Al to yield 2 moles of Fe and 1 moles of AL2O3.
If we have a
known mass of the reactant Fe2O3, we can calculate how
many moles of Al we need to fully react with the Fe2O3
using the ratio of their coefficients:
Mole ratio between Al and Fe2O3
= 2mole Al/1mole Fe2O3
Example: Using mole ratios to
calculate mass of a reactant
For the following unbalanced reaction, how many
grams of NaOH will be required to fully react with 3.10 grams of H2SO4
?
NaOH(aq)+H2SO4(aq)→H2O+Na2SO4(aq) Not balanced!
For this
reaction, we have 1 Na and 3 H on the reactant side and 2 Na and 2 H on the
product side. We can balance our equation by multiplying NaOH by two—so that
there are 2 Na on each side—and multiplying H2O on both sides. That
gives the following balanced reaction:
2NaOH(aq)+H2SO4(aq)→2H2O+Na2SO4(aq) Balanced!
Once we have
the balanced equation, we can ask ourselves the following questions:
- For which reactant(s) do we already know the amount of the chemical?
- What are we trying to calculate?
In this
example, we know the amount of H2SO4 is 3.10 grams, and
we would like to calculate the mass of NaOH. Armed with the balanced equation
and a clear sense of purpose—hopefully—we can use the following strategy to
tackle this stoichiometry problem:
Step 1: Convert known reactant
amount to moles.
The known quantity in this problem is the mass of H2SO4.
We can convert the mass of H2SO4 to moles using the
molecular weight. Given that the molecular weight of H2SO4
is 98.09 g/mol, we can find the moles of H2SO4
Step 2: Use mole ratio to find moles
of other reactant.
We are interested in calculating the amount of NaOH so
we can use the mole ratio between NaOH and H2SO4. Based
on our balanced chemical equation, we need 2 moles of NaOH for every 1 mole of
H2SO4, which gives the following ratio:
Mole ratio between NaOH and H2SO4=2mol
NaOH/1mol H2SO4 or 1mol H2SO4/2mol
NaOH
Each format
gives a different answer! However, only one ratio will allow the units of H2SO4
to cancel out properly.
Step 3: Convert moles to mass.
We can convert the moles of NaOH from Step 2 to mass
in grams using the molecular weight of NaOH:
We will need
2.53 grams of NaOH to fully react with 3.10 grams of H2SO4
in this reaction.
Shortcut: We could also combine all three
steps into a single calculation, with the caveat that we should pay extra close
attention to our units. In order to convert the mass of H2SO4
to mass of NaOH, we could solve the following expression:
If we look
carefully at the expression, we can break it down into steps 1 to 3 above. The
only difference is that instead of doing each conversion separately, we did
them all at once.
Summary
The coefficients from the balanced chemical reaction
tell us the proportions of the reactants and products. We can use ratios of the
coefficients to convert between amounts of reactants and products in our
reaction.
How to equalize chemical reactions ?
BalasHapusyou can use stoichiometry to equalize chemical reaction. and the step to equal is stoichiometric ratio
HapusExplain to me,If we Balanced reactions and mole ratios what use formula?
BalasHapusThe stoichiometric coefficients are the numbers we use to make sure our equation is balanced. We can make ratios using the stoichiometric
HapusKomentar ini telah dihapus oleh pengarang.
BalasHapus
Hapusexample
Calculate the relative formula mass of the compound with the formula: Fe2(SO4)3
Answer
(Fe = 56, S = 32, O = 16)
Fe2(SO4)3
(2 x Fe) (3 x S) (12 x O)
(2 x 56) (3 x 32) (12 x 16)
112 96 192
112 + 96 + 192 = 400
What is the difference of molarity with molality?
BalasHapusMolarity, also known as molar concentration, is the number of moles of a substance per liter of solution. Solutions labeled with the molar concentration are denoted with a capital M. A 1.0 M solution contains 1 mole of solute per liter of solution.
HapusMolality is the number of moles of solute per kilogram of solvent. It is important the mass of solvent is used and not the mass of the solution. Solutions labeled with molal concentration are denoted with a lower case m. A 1.0 m solution contains 1 mole of solute per kilogram of solvent.
The important part of remembering the difference is:
molarity - M → moles per liter solution
molality - m → moles per kilogram solvent
Can you give examples of stoichiometric application in everyday life?
BalasHapusIn practical life, battery cells, in corrosion of House painting, amount of water pollution etc. everything is measured in terms of relative weights a.k.a Atomic mass units.
HapusWhat's the use of molarity?
BalasHapusIn chemistry, molarity is a concentration unit, defined to be the number of moles of solute divided by the number of liters of solution.There are two big advantages of using molarity to express concentration. The first advantage is that it's easy and convenient to use because the solute may be measured in grams, converted
Hapusinto moles, and mixed with a volume.
The second advantage is that the sum of the molar concentrations is thetotal molar concentration. This permits calculations of density and ionic strength.
In the reaction between magnesium metal as much as 10 grams with 6 grams of oxygen according to the equation of the reaction:
BalasHapus2Mg (s) + O2 (g) 2MgO (S)
Apparently from the experiment generated 15 grams of magnesium as much as 1 gram. This fact is according to the law ..... (Ar Mg = 24, O = 16). Whether this is included in Dalton's law, lavoiser, Boyle, proust, or Gay lussac.
In the reaction between magnesium metal as much as 10 grams with 6 grams of oxygen according to the equation of the reaction:
BalasHapus2Mg (s) + O2 (g) 2MgO (S)
Apparently from the experiment generated 15 grams of magnesium as much as 1 gram. This fact is according to the law ..... (Ar Mg = 24, O = 16). Whether this is included in Dalton's law, lavoiser, Boyle, proust, or Gay lussac.
it's including in proust's law, proust's law Says that the mass ratio of elements in a compound is certain and fixed
HapusExplain to me,If we Balanced reactions and mole ratios what use formula?
BalasHapusPlease Explain the important points of the materi.?
BalasHapusUsing a balanced chemical equation to calculate amounts of reactants and products is called stoichiometry
HapusHow to Balanced reactions and mole ratios in easy way?
BalasHapusThe first and most important step for all stoichiometry problems is the same no matter what you are solving for—make sure your equation is balanced! If the equation is not balanced, the mole ratios will be wrong, and the answers will not be correct.
HapusFor example, the stoichiometric coefficients for the following balanced equation tell us that 1 mole of Fe2O3 wiil react with 2 moles of Al to yield 2 moles of Fe and 1 moles of AL2O3.
Fe2O3(s) + 2Al (s) 2Fe(l) + Al2O3
If we have a known mass of the reactant Fe2O3, we can calculate how many moles of Al we need to fully react with the Fe2O3 using the ratio of their coefficients:
Mole ratio between Al and Fe2O3 = 2mole Al/1mole Fe2O3